Q6. Two wires are 12 m and 16 m long. The wires are to be cut into pieces of
equal length. Find the maximum length of each piece.
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Answer:
4 m
Step-by-step explanation:
Maximum length of each piece = HCF of 12 and 16
12 = 2×2×3
16 = 2×2×2×2
Hence, HCF = 2×2 = 4
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