Question

Q6: What is minimum length upto which we can measure correctly with the help of slide callipers and screw
Gauge.
1. 0 0.01mm, 0.1mm
2. 0.1mm, 0.01mm
3 . 0.01mm,0,01mm
4. All​

Answer 1

Explanation:

A : Least count given (L.C)

A

=0.001mm

For B : Least count (L.C)

B

= pitch/number of circular divs =1/50=0.02mm

For C : Least count given (L.C)

C

=0.01mm

For D : (L.C)

D

= 1MSD−1VSD

Here 20VSD=19MSD or 1VSD=19/20 and in main millimeter scale 1MSD=1 mm

Thus, (L.C)

D

=(1−19/20)MSD=1/20×1mm=0.05mm

As least count of A is smallest so it will measure the smallest length and so it is more accurate.