Question

Q6. What is the area of triangle whose sides are in ratio 5:12:13 and its perimeter is 105m ?​

Answer 1

Step-by-step explanation:

a=5x

b=12x

c=13x

perimeter=105m.

so, 5x+12x+13x=105

30x=105

x=105/30

x=3.5

a=5x=5×3.5=17.5

b=12x=12×3.5=42

c=13x=13×3.5=45.5

Area by Heron's formula

$\sqrt{s(s - a)(s - b)(s - c)}$

s= 105/2

s=52.5

$\sqrt{52.5(52.5 - 17.5)(52.5 - 42)(52.5 - 45.5)}$

$\sqrt{52.5 \times 35 \times 10.5 \times 7}$

$\sqrt{135056.25}$

$367.5 {m}^{2}$

Answer 2

Answer:

A=hbb

2

b Base

hb Height the area of triangle