Question

Q6. What is the pressure inside a balloon which is inflated in a single breath of 3.5
L. (radius of balloon = 9 cm).*

Answer 1

The pressure applied to teh balloon is 140 pascal.

Explanation:

We are given that:

• Force applied on Balloon = 3.5 N
• Radius of balloon = 9 cm = 0.09 m
• To Find: Pressure applied to balloon

Solution:

We know that pressure is equal to force applied to a unit area.

Pressure = Force / Area

P = F / A

Area = πr^2 = 3.14 ( 0.09)^2

Area = 3.14 x 0.0081 = 0.025 m^2

P = 3.5 / 0.025

P = 140 N/m^2 or Pa

Thus the pressure applied to teh balloon is 140 pascal.

Answer 2

Answer :

➥ The pressure applied to the balloon = 140 N/m²

Given :

➤ Force applied on a balloon (f) = 3.5 N

➤ Radius of a balloon (r) = 8 cm

To Find :

➤ Pressure applied to the balloon = ?

Solution :

To find the pressure applied to the balloon first we need to find the area then after we find the pressure applied to the balloon.

As we know that

$\tt{:\implies Area = \pi {r}^{2} }$

$\tt{:\implies Area = \cancel{\dfrac{22}{7}} \times 0.09 \times 0.09}$

$\tt{:\implies Area = 3.14 \times 0.09 \times 0.09}$

$\tt{:\implies Area = 0.28 \times 0.09}$

$\bf{:\implies \underline{ \: \: \underline{ \green{ \: \: Area = 0.025 \: {m}^{2} \: \: }} \: \: }}$

Now ,

We find pressure applied to the balloon.

As we know that

$\tt{:\implies Pressure = \dfrac{Force}{Area}}$

$\tt{:\implies Pressure = \cancel{\dfrac{3.5}{0.025}}}$

$\bf{:\implies \underline{ \: \: \underline{ \purple{ \: \: Pressure = 140 \: N/m^2 \: \: }} \: \: }}$

Hence, the pressure applied to the balloon is 140 N/m².