Q63-In the given figure 0 is the centre of given semicircle and AB = x, BC = y.
Then DB is
(a) √xy (b) √(x + y) (c) √(x - y) (d) √(x/y)
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Answer:
Given a=
(y−z)
x
,b=
(z−x)
y
,c=
(x−y)
z
These equation can be written as
x−ay+az=0
bx+y−bz=0
−cx+cy+z=0
Since, x,y,z are not all 0, so for the consistency of system
D=0
∣
∣
∣
∣
∣
∣
∣
∣
1
b
−c
−a
1
c
a
−b
1
∣
∣
∣
∣
∣
∣
∣
∣
=0
⇒ab+bc+ac+1=0
⇒ab+bc+ac=−1
Step-by-step explanation:
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