Question

Q64 Consider two charges +30 units and +60 units placed 12 cm apart in air. Find the field intensity at the midway between two charges.
Ops: A. 0.83 dyne towards +60-unit charge
B. O 1 dyne
C. O 0.75 dyne
D. 0.83 dyne towards +30-unit charge​

Answer 1

Given that,

First charge = 30 units

Second charge = 60 units

Distance = 12 cm

We need to calculate the electric field at the midway

Using formula of electric

$E=\dfrac{kq_{1}}{x^2}+\dfrac{kq_{2}}{x^2}$

$E=\dfrac{k}{r^2}(q_{2}-q_{1})$

Put the value into the formula

$E=\dfrac{9\times10^{9}}{(6)^2}(60+30)$

$E=7.5\times10^{4}\ dyne$

Hence, The electric field at the midway is $7.5\times10^{4}\ dyne$

(C) is nearest option.

Answer 2

Given that,

First charge = 30 units

Second charge = 60 units

Distance = 12 cm

We need to calculate the electric field at the midway

Using formula of electric

$E=\dfrac{kq_{1}}{x^2}+\dfrac{kq_{2}}{x^2}$

$E=\dfrac{k}{r^2}(q_{2}-q_{1})$

Put the value into the formula

$E=\dfrac{9\times10^{9}}{(6)^2}(60+30)$

$E=7.5\times10^{4}\ dyne$

Hence, The electric field at the midway is $7.5\times10^{4}\ dyne$

(C) is nearest option.

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