Q67
If n (A) = 1000, n(B) = 500 and if n (ANB) > 1 and n (AUB) =p, then
O 500 <p < 1000
O 1001 < p < 1498
O 1000 <p < 1498
O 1000<p < 1499
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If n (A) = 1000, n(B) = 500 and if n (ANB) > 1 and n (AUB) =p, then:-
1000<p < 1499
Given, n(A) — 1000, п(В) — 500
and n( ANB) >1 and
n(AU B) = p
Therefore,
n(ANB) = n(A) + n(B) — п(A UB)
= 1000 + 500 – p
=1500 – p. | .. [Since
n(ANB) > 1]
➡️1500 - p > 1
➡️p < 1499 (i)
Also, n(A U B) > n(A)
= p > 1000 „(ii)
From Equations. (i) and (ii), we get
1000 < p < 1499
Thanks for reading.
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