Question

Q68 A machine gun has a mass of 30 kg. It fires 45g bullets at the rate of 300 bullets per minute with a speed of 600 ms. What force must be applied to the gun
to keep it in position?
Ops: A. 145N
B. 135N
C. O 120N
D. 140N​

Answer 1

The force applied to the gun to keep it in position is 135 Newtons.

Explanation:

The external force applied on the body is directly proportional to rate of change of linear momentum.

F ∝ dp

F = n × d(mv)/dt

Where,

n = Number of bullets per second = 300/60 = 5 bullets per second

m = Mass of the bullet = 0.045 kg

v = Velocity of the bullet = 600 m/s

On substituting the values, we get,

F = 5 × (0.045 × 600)/1

F = 5 × 27

∴ F = 135 N

Force applied to the bullet = Force applied by the person to keep it in position.

Answer 2

Explanation:

Given A machine gun has a mass of 30 kg. It fires 45g bullets at the rate of 300 bullets per minute with a speed of 600 ms. What force must be applied to the gun to keep it in position?

• Mass of machine gun is 30 kg
• Mass of each bullet M = 45 g = 0.045 kg
• Velocity of bullet v = 600 m/s
• Number of bullets / sec = 300 / 60 = 5
• Force required will be rate of change of linear momentum of bullets F = n mv / t
•                              = 5 x 0.045 x 600 / 1
•                             = 135 N
•   Therefore force applied to the gun will be 135 N                                                     Reference link will be

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