Q7. A cyclist starts cycling up from the bottom on a hilly road of length 50 km at 10:00 am to reach the top at a speed of 18 kmph. Another cyclist starts simultaneously from the top with a speed of 32 kmph to the bottom. The spot where the two meet each other is
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The time taken to reach the meeting point will be same for both . Let it be t
distance = speed × time
distance travelled by first = 18×t
Distance travelled by second = 32 × t
Distances travelled by both must be equal to 50km
18t + 32t = 50km
50t = 50
t = 1 hour
So, the cyclists will meet after 1 hour
point where they will meet is
18t = 18(1) = 18 km from the bottom of the hill
32t = 32(1) = 32 km from top of the hill
distance = speed × time
distance travelled by first = 18×t
Distance travelled by second = 32 × t
Distances travelled by both must be equal to 50km
18t + 32t = 50km
50t = 50
t = 1 hour
So, the cyclists will meet after 1 hour
point where they will meet is
18t = 18(1) = 18 km from the bottom of the hill
32t = 32(1) = 32 km from top of the hill
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