Question

Q7.
A floor of the room is 8 m long and 6 m wide is to be covered by square tiles. If each
square tile is 0.8 m. Find the number of tiles required to cover the floor. Also find the cost
of tiling at the rate of * 12 per tile​

Answer 1

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Given ,

The length of floor = 8 m

The breadth of floor = 6 m

The size of square tile = 0.8 m

The cost of per square tile = ₹ 7

We know that , the area of rectangle is given by

$\large \mathtt{ \underline{\fbox{Area \: of \: rectangle = length \times breadth }}}$

$\sf \hookrightarrow Area = 8 \times 6 \\ \\\sf \hookrightarrow Area = 48 \: \: {m}^{2}$

Thus , the area of floor is 48 m²

Now , the area of square is given by

$\mathtt{\large \underline{ \fbox{Area \: of \: square = {(side)}^{2} }}}$

$\sf \hookrightarrow Area = 0.8 \times 0.8 \\ \\ \sf \hookrightarrow Area = 0.64 \: \: {m}^{2}$

Thus , the area of each tile is 0.64 m²

So ,

The number of tiles required to cover the floor of the room is 48/0.64 = 75 tiles

Since , each tile costs Rs 12

∴ The total cost = 75 × 12 = Rs 900

Hence , the cost of covering the floor is Rs 900

Answer 2

Step-by-step explanation:

Area of floor = 8×6m

= 48sqm

Area of tiles = 0.8×0.8

= 0.64 sqm

Number of tiles required = 48/0.64

Cost of 1 tiling = *12 per

=12 × 48

= *576

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