Question

Q7. Calculate the force of gravitation
between two object of masses 50 kg
and 120 kg respectively kept at a
distance of 10 m from one another.​

Answer 1

40.02 × 10^-10 N is the required answer.

GIVEN:

• Mass of first object, m = 50 kg
• Mass of second object, M = 120 kg
• Distance between the objects, r = 10 m

TO FIND:

Force of gravitation, F

FORMULA:

F = (GMm) / r²

Where G is the universal gravitational constant.

G = 6.673 × 10^-11 N m^2 kg^-2.

SOLUTION:

$F= \dfrac{GMm}{ {r}^{2} } \\ \\ F = \dfrac{6.67 \times {10}^{ - 11} \times 50 \times 120}{ {(10)}^{2} } \\ F = \dfrac{6.6 7 \times 50 \times 120 \times {10}^{ - 11} }{100} \\ \\ F = \dfrac{6.67 \times 5 \times 12 \times 100 \times {10}^{ - 11} }{100} \\ \\ F = 6.67 \times 60 \times {10}^{ - 11} \\ \\ F = 6.67 \times 6 \times 10 \times {10}^{ - 11} \\ \\ F = 40.02 \times {10}^{ - 10} \: newton$

ANSWER:

The force of gravitation between the objects is 40.02 × 10^-10 N.

GRAVITATIONAL FORCE:

• It is the force responsible for the attraction between the sun and the planets.

• It is the weakest force of four fundamental forces.

• It is a long range force and is always attractive.

• The force is always conservative and central. It acts along the line joining the centre of two objects.

• This force is independent of the medium in which it is placed.

• The fundamental particle is called gravitron.