Question

Q7 Find the value of k for which the
system
2x+ky=1, 3x-5y=7 has (i) a unique
solution, and (ii) no solution.
​

Answer 1

Answer:

(i)unique solution K $\neq$ -10/3 and (ii) no solution = -10/3

Step-by-step explanation:

2x+ky=1,

3x-5y=7

(i) For unique solution :

=> a1/a2 $\neq$ b1/b2

=> 2/3 $\neq$ -k/5

=> k $\neq$ -10/3

(ii) For no solution :

=> a1/a2 = b1/b2 $\neq$ c1/c2

=> 2/3 =  -k/5

=> k = -10/3

Hope this helps

           :)