Q7: from the given figure 7, find the value of x if AB ll CF (AB is parallel to CF) and AE=DE, (angle)BAE=38 degrees.
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I didn't understand the question properly
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Angle BAE = angle AED (Alternate interior angles)
We know that angle EAD = angle ADE
Therefore 180 - 38 = EAD * 2 = ADE * 2
EAD = ADE = 71
And finally we can conclude that x = 180 - 71 = 109
We know that angle EAD = angle ADE
Therefore 180 - 38 = EAD * 2 = ADE * 2
EAD = ADE = 71
And finally we can conclude that x = 180 - 71 = 109
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