Math, asked by rishabh220804, 11 months ago

Q7. If sec ɵ - tan ɵ=1/2 then the value of secɵ+tanɵ is

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Answers

Answered by BrainlyPopularman
5

ANSWER :

2

SOLUTION :

GIVEN :

sec(ɵ) - tan(ɵ) = ½

TO FIND :

Value of sec(ɵ) + tan(ɵ).

SOLUTION :

We know that –

• sec²(ɵ) - tan²(ɵ) = 1

We know one other property –

a² - b² = (a + b)(a - b)

So that –

[sec(ɵ) - tan(ɵ)][sec(ɵ) + tan(ɵ)] = 1

sec(ɵ) + tan(ɵ) = 1/{sec(ɵ) - tan(ɵ)}

According to the question –

=> sec(ɵ) + tan(ɵ) = 1/(½)

=> sec(ɵ) + tan(ɵ) = 2

Answered by Anonymous
6

__________________________

\huge\tt{PROBLEM:}

  • If sec ɵ - tan ɵ=1/2 then the value of secɵ+tanɵ is

__________________________

\huge\tt{SOLUTION:}

we know that,

↪sec²(∅) - tan²(∅) = 1

Then,

↪[sec(∅)-tan(∅)][sec(∅)+tan(∅)] = 1

↪[sec(∅)+tan(∅)] = 1/[sec(∅)-tan(∅)]

Now,

↪[sec(∅)+tan(∅)] = 1(½)

↪sec(∅)+tan(∅) = 2

__________________________

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