Q7. If sec ɵ - tan ɵ=1/2 then the value of secɵ+tanɵ is
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ANSWER :–
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SOLUTION :–
GIVEN :–
• sec(ɵ) - tan(ɵ) = ½
TO FIND :–
Value of sec(ɵ) + tan(ɵ).
SOLUTION :–
➪ We know that –
• sec²(ɵ) - tan²(ɵ) = 1
➪ We know one other property –
• a² - b² = (a + b)(a - b)
➪ So that –
• [sec(ɵ) - tan(ɵ)][sec(ɵ) + tan(ɵ)] = 1
• sec(ɵ) + tan(ɵ) = 1/{sec(ɵ) - tan(ɵ)}
➪ According to the question –
=> sec(ɵ) + tan(ɵ) = 1/(½)
=> sec(ɵ) + tan(ɵ) = 2
Answered by
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- If sec ɵ - tan ɵ=1/2 then the value of secɵ+tanɵ is
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we know that,
↪sec²(∅) - tan²(∅) = 1
Then,
↪[sec(∅)-tan(∅)][sec(∅)+tan(∅)] = 1
↪[sec(∅)+tan(∅)] = 1/[sec(∅)-tan(∅)]
Now,
↪[sec(∅)+tan(∅)] = 1(½)
↪sec(∅)+tan(∅) = 2
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