Question

Q7. Nitrogen and hydrogen
combine in the ratio of 14:3 by
mass to form ammonia. What
mass of nitrogen gas would be
required to react completely
with 9g of hydrogen gas?​

Answer 1

Answer:

b Molecular mass of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g.

Explanation:

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Answer 2

Answer:

your answer is

Explanation:

b molecular mass ammonia NH3 = mass of N + mass of H = 14+3 × 1 = 17 To react with 14 g N mass of H required = 3g Therefore to react with 42 g N mass of H required = 3/14 × 42 = 9g.

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