Question

Q7 The diagonals of a rhombus are 16 cm and 12 cm, find a) Its area b) Its length of the side e) lis perimeter​

Answer 1

Answer:

Area of rhombus = 1/2(Product of diagonals)

Area = 1/2(12*16)

= 96 cm^2

Diagonals of rhombus are perpendicular bisects each other so in as per this property a right angled triangle formed so by Pythagoras theorem side of rhombus will be hypotenuse of that triangle

side will be

H^2= 6^2 + 8^2

36+64 = 100

side= 10 cm

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Step-by-step explanation:

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Answer 2

Answer:

we know,

Area of rhombus = ½* (b*h)

= ½ * 192

= 96 cm²

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