Question

Q7 The sum of first 26 terms of the A.P. 6,2.......is.....​

Answer 1

Answer:

sn=n/2(2a+n-1*d

26/2(12+25*-4

13(12-100)

13*88

-1144

Answer 2

Answer:

-1144

Step-by-step explanation:a=6 d=-4

Sn=n/2{2a+(n-1)d} =26/2{2*6(26-1)-4}. 13{12+25*(-4)}. 13*(12-100). 13*(-88). =-1144 ans.