Question

Q7. The taxi fare in a town is Rs. 10 for the first km and Rs. 6 per km for the subsequent distance. Taking distance as 'x' km and the total fare as Rs. 'y', write a linear equation for this information, what will be the total fare for 15km?​

Answer 1

ANSWER:

Given:

• Fare for 1st km= Rs 10
• Fare for subsequent distance = Rs 6/km

To Find:

• Linear equation for the information given
• Total fare for 15km.

Solution:

We are given that,

⇒Fare for 1st km= Rs 10

Let the total distance covered be x and total fare be y.

⇒Fare for subsequent distance = Rs 6/km

So,

⇒Fare for next kilometre = Rs 6

Hence,

⇒Fare for next (x - 1) kilometre = Rs 6(x - 1)

⇒Total fare = 10 + 6(x - 1)

But, total fare is assumed to be y.

Hence,

⇒y = 10 + 6(x - 1)

⇒y = 10 + 6x - 6

⇒y = 6x + 4.

Hence, the linear equation of the given information is y = 6x + 4.

Now,

⇒Total fare for 15km = 6(15) + 4

⇒Total fare for 15km = 90 + 4

⇒Total fare for 15km = Rs 94

Hence, the total fare for 15km is Rs 94.