Question

Q7 Two angles of triangle are equal and the third angle is greater than each of these angles by
30°. Find all the angles of a triangle.​

Answer 1

Answer:

let the equal angles be x

3rd angle=x+30

x+x+x+30=180

3x+30=180

3x=180-30

3x=150

x=150/3

x=50

3rd angle =50+30=80degree

HOPE THIS HELPS!