Q7. Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given ahead table: Sum 2 3 4 5 6 7 8 9 10 11 12 Frequency 14 30 42 55 72 75 70 53 46 28 15 If the dice are thrown once more, What is the probability of getting a sum i) 3? ii) More than 10? iii) Less than or equal to 5? iv) Between 8 and 12?
Answers
Answered by
218
Sum 2 3 4 5 6 7 8 9 10 11 12
Frequency 14 30 42 55 72 75 70 53 46 28 15
Total outcomes=500
i)P[of getting a sum 3]=30/500
=3/50
=0.06
ii)P[of sum more than 10]=89/500
=17.8/100
=0.178 {NOT SURE}
iii)P[sum less than or equal to 5]=141/500
=28.2/100
=0.282
iv)P[sum between 8 and 12]=127/500
=25.4/100
=0.254 {NOT SURE}
Frequency 14 30 42 55 72 75 70 53 46 28 15
Total outcomes=500
i)P[of getting a sum 3]=30/500
=3/50
=0.06
ii)P[of sum more than 10]=89/500
=17.8/100
=0.178 {NOT SURE}
iii)P[sum less than or equal to 5]=141/500
=28.2/100
=0.282
iv)P[sum between 8 and 12]=127/500
=25.4/100
=0.254 {NOT SURE}
Answered by
119
Answer:
total outcomes=500
i. P( getting a sum 3 )=30/500=0.06
ii. P (getting a sum of more than 10 )= 28+15/500=0.086
iii. P ( less than or equal to 5 ) =14+30+42+55/500= 141/500 =0.282
iv. P ( between 8 and 12 ) =53+46+28/500=127/500
= 0.254
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