Math, asked by RAGHUL5366, 1 year ago

Q7. Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given ahead table: Sum 2 3 4 5 6 7 8 9 10 11 12 Frequency 14 30 42 55 72 75 70 53 46 28 15 If the dice are thrown once more, What is the probability of getting a sum i) 3? ii) More than 10? iii) Less than or equal to 5? iv) Between 8 and 12?

Answers

Answered by Anonymous
218
Sum            2  3    4    5  6    7   8   9   10  11  12
Frequency 14 30 42 55 72 75 70 53 46 28 15 
Total outcomes=500
i)P[of getting a sum 3]=30/500
                                    =3/50
                                    =0.06
ii)P[of sum more than 10]=89/500
                                         =17.8/100
                                         =0.178                  {NOT SURE}
iii)P[sum less than or equal to 5]=141/500
                                                     =28.2/100
                                                     =0.282
iv)P[sum between 8 and 12]=127/500
                                              =25.4/100
                                              =0.254                 {NOT SURE}
Answered by noorafshan9421
119

Answer:

total outcomes=500

i. P( getting a sum 3 )=30/500=0.06

ii. P (getting a sum of more than 10 )= 28+15/500=0.086

iii. P ( less than or equal to 5 ) =14+30+42+55/500= 141/500 =0.282

iv. P ( between 8 and 12 ) =53+46+28/500=127/500

= 0.254

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