Q7. Two pipes can fill a tank in 5 hours and 6 hours respectively while a third pipe empties the full tank in 10 hours if all the three pipes operate simultaneously. In how much time tank will be full?
Answers
Answered by
1
Answer:
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Step-by-step explanation:
LCM(5,6,12)=60
Suppose capacity of the tank is 60l. Then, quantity filled by pipe A in 1hr =
5
60
=20l
Quantity filled by pipe B in 1hr =
6
60
=10l
Quantity filled by pipe C in 1hr =
12
60
=5l
Quantity filled in 1hr if all the three pipes are opened together=12+10−5=17l
Required time=
17
60
=3
17
9
hrs.
Answered by
0
Answer:
3.75 hour
Step-by-step explanation:
x=5
x=5y=6
x=5y=6x=10
FORMULA:- XYX/YZ+XZ-XY
=5×6×10/6×10+5×10-5×6
=300/80
=3.75 Hours
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