Question

Q7.Two plane mirrors M^1 and M^2 are placed at a right angle. A ray of light is incident on M^1 at P^1 and gets
reflected from M^1 . It then gets reflected from M^2 at P^2 .

If OP^1 = OP^2 , then what is the angle of reflection of the ray at P^2 ?

Answer 1

Answer:

Two plane mirror M

1

and M

2

have their reflecting faces inclined at θ. Mirror M

1

receives a ray AB,reflects it at B and sends it as BC.It is now reflected by mirror M

2

along CD,as shown in the figure.Total angular deviation δ suffered by the incident ray AB is

Answer

δ

1

=180−2i

1

δ

2

=180−2i

2

Also,θ+(90−i

1

)+(90−i

2

)=180

=θ+180−i

1

−i

2

=180

=θ=i

1

+i

2

S

net

=δ

1

+delta

2

=360−2(i

1

+i

2

)

=360−2(θ)

=360−2θ

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Answer 2

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given : ∠i+∠r=80

0

Solution: ∠i+∠r=80

0

→(1)

and for a plane mirror

∠i=∠r →(2)

then from (1) and (2)

2∠i=80

0

∠i=40

0