Question

Q7: What is the decimal equivalent of a binary number 111000111?​

Answer 1

Answer:-

${111000111}_{2} = {?}_{10}$

$= {1.2}^{8} + {1.2}^{7} + {1.2}^{6} + {0.2}^{5} + {0.2}^{4} + {0.2}^{3} + {1.2}^{2} + {1.2}^{1} + {1.2}^{0}$

$= 256 + 128 + 64 + 0 + 0 + 0 + 4 + 2 + 1$

$= 445$

$∴{111000111}_{2} = {455}_{10}$

@BengaliBeauty

Feel free to ask your doubts anytime