Question

Q71. If (x-7) 2 + (y + 10) 2 + (z - 6) 2 = 0, then find the value of
X+y+z.
(a) 1
(b)3
(C) 5
(d) 7​

Answer 1

Answer:

(b) 3 is the answer

Step-by-step explanation:

(x-7)2 + (y+10)2 + (z-6)2 = 0

2x - 14 + 2y + 20 + 2z - 12 = 0

2x + 2y + 2z = 6

2(x + y + z) = 6

x + y + z = 6/2 = 3

Answer 2

Answer:

2x-14+2y+20+2z-12=0

2x+2y+2z-26+20=0

2x+2y+2z-6=0

2x+2y+2z=6

2(x+y+z)=6

x+y+z=6÷2=3

hence, 3 is the answer