Q8. A force of 120 N acts on the surface of area 5 cm square. What would be the pressure exerted on the surface? * Q8. A force of 120 N acts on the surface of area 5 cm square. What would be the pressure exerted on the surface? *
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F = 120N
A =5 cm^2
P=F/A=120/5=25 pascals
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Answer:
240000
Explanation:
F=120N
A=5cm^2=5×10^-4 m^2
P=F/A = 120/5×10^-4= 24×10^4 (ANS)
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