Math, asked by arnab7258, 1 year ago

Q8 A sweet seller has 420 kaju burfis and 130 badam burfis. He wants to stack them in such a way that each stack has the same number and they take up the least area of the tray. What is the number of burfis that can be placed in each stack?

Answers

Answered by TANU81
28
❣️Hi there❣️

We find H.C.F

420 = {2}^{2} \times 3 \times7 ×5 \\ \\ 130 = 2 \times 5 \times 13 \\ \\ so \: commonfactor \: is \: 2 \: and \: 5 \\ \\
=2 ×5 = 10

Therefore , the sweet seller can make stacks of 10 for both kinds of barfi..

Hope it will helpful ☺️

TANU81: :)
siddhartharao77: 420 = 2^2 * 3 * 5 * 7.
Answered by jaya1012
16
hii. ......friend

the answer is here,

We have to find HCF,

 = > \: 420 = {2}^{2} \times 3 \times 7 \times 5

 = > \: 130 = 2 \times 5 \times 13

So, The HCF => 2×5 =10.

So, The sweet seller can make stacks of 10 for both kind of burfis.


:-)Hope it helps u.
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