Question

Q8. ABC is a right angled triangle right angled at B, the difference between the two shorter sides is equal to 2cm and the square of the longest side is 100. What is the length of the two shorter sides?

(A) 4 & 6
(B) 5 & 7
(C) 6 & 8
(D) 7 & 9​

Answer 1

Answer:

(C) 6&8

Step-by-step explanation:

let the shorter side be x and (x-2)

by Pythagoras,

x2. + (x-2)^2 = 100

x^2 + x^2 + 4 - 4x = 100

2x^2 - 4x - 96 =0

x^2 - 2x - 48 = 0

x^2 -8x + 6x - 48 = 0

x(x - 8 ) +6 (x - 8 ) = 0

(x-8)(x+6)=0

x = +8. , -6

side cannot be negative

so first side is x= 8

and second is = (x-2) = 8-2 = 6

Answer 2

Answer:

c

Step-by-step explanation:

sides?

(A) 4 & 6

(B) 5 & 7

(C) 6 & 8

(D) 7 & 9