Question

Q8.)



An aqueous solution of 6.3 g of oxalic acid dehydrate is made up to 250 ml. The volume of 0.1 N NaOH required to completely neutralize 10 ml of this solution is

A) 20 ml

B) 10 ml

C) 40 ml

D) 50 ml

explain

Answer 1

HEY FOLK...


Molecular formula of Oxalic acid dehydrate = H2C2O4 . 2H2O

Molecular mass of Oxalic acid dehydrate = 126

Since it is dibasic acid so,

equivalent weight = moleculas mass / 2

                         = 126/2

                         = 63

Normality = given mass / eq. wt. × volume ( litre )

               = 6.3/63 × 1000/250

               = 0.4 N

we know that,

 N1V1 = N2V2

 0.1 ×V1 = 0.4 × 10

Therefore, V1 = 40 mL.

HOPE IT HELPS...

#Mme