Question

Q8. Calculate number of moles of NH3 formed by reaction of 2 moles of N2 and 2
moles of H2

Answer 1

Answer:

N2 + 3H2 ---- 2NH3

THIS IS THE REACTION FOR THE FORMATION OF AMMONIA AND WE CANNOT HAVE H2 WITH 2 MOLES IN THIS REACTION.

NO.OF MOLES OF NH3 WILL BE 2 .

NO.OF MOLES OF H2 WILL BE 2.

NO.OF MOLES OF N2 WILL BE 1.

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.HOPE IT helped.

Answer 2

Answer:

The number of moles of NH₃ formed by the reaction of 2 moles of  N₂ gas and H₂ gas will be equal to 1.33 moles.

Explanation:

The balanced chemical reaction for the formation of ammonia:

       $N_{2} (g)\; \;+\; \; 3H_{2} (g)$    ⇆    $2NH_{3}\;(g)$

From the above reaction, we can say that 2 moles of NH₃ will be produced by the reaction of 1 moles of nitrogen and 3 moles of hydrogen gas.

1 moles of N₂ gas produced = 2 moles of NH₃

2 moles of  N₂ gas will produce = 4 moles of  NH₃

Now, for hydrogen gas,

3 moles of  H₂ gas produced = 2 moles of NH₃

2 moles of H₂ gas will produce  $=\frac{2}{3} *2=\frac{4}{3} =1.33$  moles of  NH₃

Here, hydrogen gas will be act as a limiting reagent. Once the 2 moles of hydrogen gas will be consumed, there will be no more hydrogen left to react with  N₂ gas to produce further ammonia.

Therefore, the number of moles of  NH₃ formed is equal to 1.33 moles.