Q8) Calculate the no. of molecules in a drop of water weighing 0.05 g.
Answers
Answered by
13
HEYA......
Molecular mass of water = 18 g.
No. of moles in 0.05 g of water = 0.05/18
.= 2.78 x 10-3 mol.
= 1.67 x 1021 molecules.
TYSM...#
Molecular mass of water = 18 g.
No. of moles in 0.05 g of water = 0.05/18
.= 2.78 x 10-3 mol.
= 1.67 x 1021 molecules.
TYSM...#
Answered by
24
Hey mate!
Here's your answer!!
Molecular mass of water = 18 g
No. of moles in 0.05 g of water = 0.05/18
= 2.78 x 10^-3 mol
One mole = 6.023 x 10^23 molecules
Therefore, 2.78 x 10^-3 mol of water contain
= 2.78 x 10^-3 6.023 x 10^23 molecules
= 1.67 x 10^21 molecules
✌ ✌ ✌
#BE BRAINLY
Here's your answer!!
Molecular mass of water = 18 g
No. of moles in 0.05 g of water = 0.05/18
= 2.78 x 10^-3 mol
One mole = 6.023 x 10^23 molecules
Therefore, 2.78 x 10^-3 mol of water contain
= 2.78 x 10^-3 6.023 x 10^23 molecules
= 1.67 x 10^21 molecules
✌ ✌ ✌
#BE BRAINLY
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