Question

Q8. Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32 cm.​

Answer 1

Answer:

area is in m square not in cm ok ?

Answer 2

Answer:

perimeter of triangle =a+b+c

32=8+11+c

32-19=c

13=c

s=a+b+c/2

=8+11+13/2

=16

area of triangle =

$\sqrt{s{s - a} {s - b}{s - c}}$

= 16(16-8)(16-11)(16-13)

=16×8×5×3

=2×2×2×2×2×2×2×5×3

=8√30cm²