Question

Q8. Find the perimeter of the figure obtained by joining the
mid-points of a square of side 16 cm [Take (N2) = 2] .
ained by joining the​

Answer 1

Step-by-step explanation:

Taking the midpoint of 2 adjacent sides and forming a triangle abc, ab=8cm(midpoint)

bc=8cm(midpoint)

Since all angles of a square are 90, angle abc=90, Using Pythagoras theorem

8^2+8^2=AC^2

128=AC^2

AC=root of 128

AC=11.31cm

Similarly doing this on all 4 adjacent sides will give you that the side of figure inside the square is 11.31cm. Perimeter= 4 x 11.31= 45.24cm  

Answer 2

Answer:

Perimeter= 4 x 11.31= 45.24cm

Step-by-step explanation:

Step-by-step explanation:

Taking the midpoint of 2 adjacent sides and forming a triangle abc, ab=8cm (midpoint)

bc=8cm (midpoint)

Since all angles of a square are 90, angle abc=90, Using Pythagoras theorem

8^2+8^2=AC^2

128=AC^2

AC=root of 128

AC=11.31cm

Similarly doing this on all 4 adjacent sides will give you that the side of figure inside the square is 11.31cm.