Question

Q8. If y=-1 is a zero of the polynomial q (y) = 4y3 + ky2 - y -1, then find the value of k
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Answer 1

Answer:

k = 4

Step-by-step explanation:

$4 {y}^{3} + k {y}^{2} - y - 1 = 0 \\ y = - 1 \\ 4 {( - 1)}^{3} + k {( - 1)}^{2} - ( - 1) - 1 = 0 \\ 4( - 1) + k(1) + 1 - 1 = = \\ - 4 + k + 1 - 1 = 0 \\ - 4 + k = 0 \\ k = 4$

Hope you get your answer