Question

Q8. In the given figure, O is the
centre of the circle of the circle
of radius 5cm. OPLAB,
OQICD, AB || CD, AB = 6cm
and CD = 8cm. PQ is equal to
*​

Answer 1

Answer:

please find the pc value pc value = pq value

Answer 2

Answer:

PQ is =1 cm

Step-by-step explanation:

⇉Join OA and OC

⇉

$ab = pb = \frac{1}{2} \: ab = 3cm$

⇉

$and \: cq = qd = \frac{1}{2} \: \: cd = 4cm$

⇉In the Right Angeled Triangle

⇉OAP, we have

⇉OA²=OP²+AP² (Using Pythagoras Theorum)

⇉5²=OP²+3²=16cm

⇉OP=4cm²

⇉In Right Angeled Triangle

⇉OCQ,We have

⇉OC²=OQ²+CQ²

⇉5²=OQ²+4²

⇉OQ²=5²-4²=9cm²

⇉OQ=3cm

⇉PQ=PO-OQ

⇉OP=OQ=(4-3)cm

⇉1cm

⇉So Hence,PQ is 1cm....