Q8. Show that the given equation has real roots, and hence find its root by quadratic formula
![\sqrt{3x}^{2} + 11x + 6 \sqrt{3 }= 0 \sqrt{3x}^{2} + 11x + 6 \sqrt{3 }= 0](https://tex.z-dn.net/?f=+%5Csqrt%7B3x%7D%5E%7B2%7D+%2B+11x+%2B+6+%5Csqrt%7B3+%7D%3D+0)
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√3x2 + 11x + 6√3 = 0
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asked Feb 7, 2019 in Class X Maths by aditya23 (-2,151 points)
√3x2 + 11x + 6√3 = 0
quadratic equation
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answered Feb 7, 2019 by navnit40 (-4,941 points)
√3x2 + 11x + 6√3 = 0
⇒ √3x2 + 9x + 2x + 6√3 = 0
⇒ √3x(x + 3√3) + 2(x + 3√3) = 0
⇒ (x + 3√3)(√3x + 2) = 0
x + 3√3 = 0
or √3x + 2 = 0
⇒ x = -3√3
Or x = - 2/√3 are two roots of the equation.
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Q8. Show that the given equation has real roots, and hence find its root by quadratic formula
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