Question

Q8. The dimensions of a are 12m by 8m by 4m . Calculate the area of its four walls.​

Answer 1

Given:-

• Length ,L = 12m
• Breadth ,B = 8cm
• Height ,H = 4m

To Find:-

• Area of its four wall (LSA)

Solution:-

According to the Question

It is given that ,

The dimensions of wall are 12m by 8m by 4m respectively.

We have to calculate the area of its four wall.

• Area of four walls = 2(L+B)H

where,

• L denote length
• B denote Breadth
• H denote Height

Substitute the value we get

$\longrightarrow$ Area of four walls = 2(12+8) 4

$\longrightarrow$ Area of Four Walls = 2(20)4

$\longrightarrow$ Area of Four Walls = 40×4

$\longrightarrow$ Area of Four Walls = 160m²

• Hence the area of its four walls is 160m².

Answer 2

Answer:-

• L=12m
• B=8m
• H=4m

Its a Cuboid and we have to find LSA

☆LSA=2(L+B)×H

$\\ \qquad\quad\sf\longmapsto LSA=2(12+8)\times 4$

$\\ \qquad\quad\sf\longmapsto LSA=2(20)\times 4$

$\\ \qquad\quad\sf\longmapsto 2\times 80$

$\\ \qquad\quad\sf\longmapsto LSA= 160m^2$