Question

Q8. Which of the following will
contain maximum number of
moles a) 44g CO2 [Atomic
mass of C=12u ,O=16u] b) 8g of
H2 [Atomic Mass of H=1u].
*​

Answer 1

Explanation:

using the formula no of mole=given mass/molar mass

no of moles in CO2=44/44=1 mole

no of moles in H2=8/2=4 mole

so H2 will contain maximum number of moles

Answer 2

no:of moles =

[given weight / molecular weight]×N

molecular weight of CO2 = 44

=> no:of moles = 44/44 × N = N

molecular weight of H2 = 2

=> no:of moles = 8/2 × N = 4N

so, 8g of H2 have more no:of moles