Chemistry, asked by charan4736, 1 month ago

Q82 The photochemical dissociation of chlorine results in the production of two chlorine atoms , one .in the ground state and another in the excited stat
Cl2 -- CI+ CI
The maximum wavelength () needed for this is 174 nm. If the excitation energy.for cl -- cl* is 3.15 ×10 -¹⁹ J , then how much energy is needed for.such
dissociation of one mole of chlorine into normal atoms?
Ops: A
O 600 kJ/ Mol
B.
O 550 kJ/ Mol
c. 150 kJ/ Mol
D.
O 500 kJ/ Mol​

Answers

Answered by rapidninja2277
8

Answer:

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Answered by manishad
0

Answer:

D) 500 kJ mol​⁻¹ approximately is the right answer.

Explanation:

Energy required per molecule in the process,

Cl₂ ⇒ Cl + Cl  may be given as

E=hc/λ = 6.626×10⁻¹⁶×3×10⁸ / 174×10⁻⁹

=11.424×10⁻¹⁹ J mol⁻¹

Energy for Cl ⇒ Cl * is 3.15×10⁻¹⁹ J

Then energy for Cl₂ ⇒ 2Cl will be,

11.424×10⁻¹⁹ −3.15×10⁻¹⁹ = 8.274×10⁻¹⁹ J

For one mole = E × NA (Avogadro number)

=8.247×10⁻¹⁹ × 6.023×10²³

=498.3 kJ mol−1

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