Math, asked by alinsaftanzeem304, 8 months ago

Q85) The simple interest on a sum of Rs. 4800 for 2 years is Rs.768. What will be the compound interest
on the same sum at the same rate and for the same period.
(A) Rs. 870.75 (B) Rs. 920.69
(C) Rs. 798.72 (D) Rs. 884.20

Answers

Answered by Anonymous
14

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\huge\bold\red{\underline{\underline{{Question:}}}}

  • The simple intrest of a sum of Rs 4800 for 2 years is Rs 768 what will be the compound intrest on the same sum at the same rate and for the same period.

\huge\bold\red{\underline{\underline{{Answer:}}}}

  • (C) Rs. 798.72

\large\bold\blue{\underline{\underline{{Given:-}}}}

  • Principal, p = Rs. 4800

  • Time = 2 years

  • Interest = Rs. 768

\large\bold\green{\underline{\underline{{Answer:-}}}}

  • Find the Compound Interest.

\large\bold\orange{\underline{\underline{{Solution:-}}}}

✍️Simple Interest formula :-

{\boxed{{\bf{Simple \: interest \:  = \frac{Pnr}{100}  }}}}

 \sf\large\pink{ ⇝\frac{Pnr}{100} = 768 }

 \sf\large\pink{⇝  \frac{4800 \times 2 \times r}{100} = 768  }

 \sf\large\pink{⇝ 48 \times 2 \times r = 768}

 \sf\large\pink{⇝ r = 8}

✍️Compound Interest formula :-

{\boxed{{\bf{Compound \: interest \:  = P(1 +  \frac{r}{100}  {)}^{n} - P }}}}

 \sf\large{ ⟹ 4800(1 +  \frac{8}{100} {)}^{2}   - 4800}

 \sf\large{⟹ 4800(1 +  \frac{2}{25} {)}^{2}   - 4800}

 \sf\large{⟹ 4800(\frac{27}{25} {)}^{2}   - 4800}

 \sf\large{⟹ 4800 \times 100(\frac{27}{25} {)}( \frac{27}{25} )   - 4800}

 \sf\large{ ⟹ 192( \frac{729}{25})  - 4800}

 \sf\large{ ⟹ 192( 29.16)  - 4800}

 \sf\large{ ⟹ 5598.72  - 4800}

 \sf{⟹ Rs.798.72}

✧ So, The compound Interest = Rs.798.72.

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Answered by Anonymous
5

Answer:

_______________________________________

\huge\bold\red{\underline{\underline{{Question:}}}}

Question:

The simple intrest of a sum of Rs 4800 for 2 years is Rs 768 what will be the compound intrest on the same sum at the same rate and for the same period.

\huge\bold\red{\underline{\underline{{Answer:}}}}

Answer:

(C) Rs. 798.72

\large\bold\blue{\underline{\underline{{Given:-}}}}

Given:−

Principal, p = Rs. 4800

Time = 2 years

Interest = Rs. 768

\large\bold\green{\underline{\underline{{Answer:-}}}}

Answer:−

Find the Compound Interest.

\large\bold\orange{\underline{\underline{{Solution:-}}}}

Solution:−

✍️Simple Interest formula :-

{\boxed{{\bf{Simple \: interest \: = \frac{Pnr}{100} }}}}

Simpleinterest=

100

Pnr

\sf\large\pink{ ⇝\frac{Pnr}{100} = 768 }⇝

100

Pnr

=768

\sf\large\pink{⇝ \frac{4800 \times 2 \times r}{100} = 768 }⇝

100

4800×2×r

=768

\sf\large\pink{⇝ 48 \times 2 \times r = 768}⇝48×2×r=768

\sf\large\pink{⇝ r = 8}⇝r=8

✍️Compound Interest formula :-

{\boxed{{\bf{Compound \: interest \: = P(1 + \frac{r}{100} {)}^{n} - P }}}}

Compoundinterest=P(1+

100

r

)

n

−P

\sf\large{ ⟹ 4800(1 + \frac{8}{100} {)}^{2} - 4800}⟹4800(1+

100

8

)

2

−4800

\sf\large{⟹ 4800(1 + \frac{2}{25} {)}^{2} - 4800}⟹4800(1+

25

2

)

2

−4800

\sf\large{⟹ 4800(\frac{27}{25} {)}^{2} - 4800}⟹4800(

25

27

)

2

−4800

\sf\large{⟹ 4800 \times 100(\frac{27}{25} {)}( \frac{27}{25} ) - 4800}⟹4800×100(

25

27

)(

25

27

)−4800

\sf\large{ ⟹ 192( \frac{729}{25}) - 4800}⟹192(

25

729

)−4800

\sf\large{ ⟹ 192( 29.16) - 4800}⟹192(29.16)−4800

\sf\large{ ⟹ 5598.72 - 4800}⟹5598.72−4800

\sf{⟹ Rs.798.72}⟹Rs.798.72

✧ So, The compound Interest = Rs.798.72.

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