History, asked by sonukumar3621705, 7 months ago

Q9.7 How many solutions of these
equations x-y=8, 3x-3y=16 have *
One
Two
No
Many​

Answers

Answered by iamyourdad007
0

Answer:

no answer

Explanation:

the lines are parallel

Answered by parevaprerna
0

Answer:

sol- given,

x-y=8 ----- eq.1

3x-3y=16 -----eq.2

now,

from equation 1

if x =0

x-y=8

0-y=8

-8=y

y= -8

if x=1

x-y=8

1-y=8

1-8=y

-7=y

y= -7

if x=2

x-y=8

2-y=8

2-8=y

-6=y

y= -6

                                        table-1

     x      0         1         2

     y     -8        -7       -6

from equation --- 2

3x-3y=16

if x=0

3x-3y=16

3.0-3y=16

-3y=16

y=16/-3

y= -5.3

if x=1

3x-3y=16

3.1-3y=16

-3y=16-3

y=13\-3

y= -4.3

if x =2

3x-3y=16

3.2-3y=16

6-3y=16

-3y=16-6

y=10\-3

y= -3.3

                                               table-2

     x          0              1                 2

    y           -5.3         -4.3            -3.3

since, it is a no solution.

i hope this s correct ans.

Explanation:

Similar questions