Q9. A manufacture produces three stationary products penal eraser & sharpener which he sells in two markets Annual sales are indicated below Product in numbers Market Pencil Eraser Sharpener А 10,000 2,000 18.000 B 6.000 20.000 8.000 fund sale pnce o Pencd Eraser & Sharpenerare Rs 2.50. Rs 1.50 3 Rs. 100 respectively & unit cost of above three commodities are Rs 200. Rs 100 & Rs. 0.5 respectively, then based on above information answer the following 1. Total revenue of market A is: (use matrix multiplication)
Answers
Answer:
(a) The unit sale prices of x,y and z are respectivelyRs.2.50,Rs.1.50 and Rs.1.00.
Total revenue in market I can be represented as:
[
10000
2000
18000
]
⎣
⎢
⎢
⎡
2.50
1.50
1.00
⎦
⎥
⎥
⎤
=10000×2.50+2000×1.50+18000×1.00
=25000+3000+18000
=46000
Total revenue in market II can be represented as:
[
6000
20000
8000
]
⎣
⎢
⎢
⎡
2.50
1.50
1.00
⎦
⎥
⎥
⎤
=6000×2.50+20000×1.50+8000×1.00
=15000+30000+8000
=53000
So, the total revenue in market I is Rs 46000 and in market II is Rs.53000.
(b) The unit cost prices of x,y and z are respectively given as Rs.2.00, Rs.1.00 and 50 paise.
So, the total cost prices of all the products in market I can be represented as:
[
10000
2000
18000
]
⎣
⎢
⎢
⎡
2.00
1.00
0.50
⎦
⎥
⎥
⎤
=10000×2.00+2000×1.00+18000×0.50
=20000+2000+9000
=31000
Since, the total revenue in market I is Rs.46000.
So, the gross profit in this market is Rs46000−Rs31000=Rs15000.
The total cost prices of all the products in market II can be represented as:
[
6000
20000
8000
]
⎣
⎢
⎢
⎡
2.00
1.00
0.50
⎦
⎥
⎥
⎤
=6000×2.00+20000×1.00+8000×0.50
=12000+20000+4000
=Rs36000
Since, the total revenue in market II is Rs.53000.
So, the gross profit in this market is Rs.53000−Rs.36000=Rs.17000