Question

Q9. An object of mass 2 kg is dropped from a height of 1m. What will be its kinetic
energy as it reaches the ground? (take g=9.8m/s2)​

Answer 1

Answer:

Explanation:

The kinetic energy as it touches the ground is 20J.

Explanation:

The body being dropped from a height acquires kinetic energy during the motion which  is calculated using equation of motion and formula of kinetic energy as follows -

Given: Initial velocity = u = 0

Acceleration a = g

Height h = 1 m

Final velocity v = ?

From equation of motion, we have –

k.e= 1/2 mv²

but to find v we use

v²-u² =2as

v²-0= 2×10×1

then v =√20

K.E. = 20 J

Answer 2

Answer:

20joules is the write answer

Explanation:

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