Question

Q9: Diameter of a circular park is 70m. A path of width 2m runs outside around it. Find the area of
path.​

Answer 1

Required answer:-

Question :

• Diameter of a circular park is 70m. A path of width 2m runs outside around it. Find the area of path.

Solution :

Given,

Diameter of circular park = 70m

Width of path = 2m

To find:

• Area of path

Formulas used:

♦ Radius of outer circle = r + width of path

♦ Area of path = π ( R² - r² )

( That is R² is outer radius and r² is inner radius )

Step by step explaination:

First calculate the radius of inner circle

That is,

radius of inner circle = 70/2 m

= 35 m

Now we have to calculate the radius of outer circle

That is,

Radius of outer circle = r + width of path

= (35 + 2) m

= 37m

Now we have to calculate the area of path

That is,

Area of path = π ( R² - r² )

= 3.14 ( 37² - 35²)

= 3.14 × 144m²

= 452.16 m²

Area of path is 452.16 m²

Answer 2

Given Question :-

• Diameter of a circular park is 70m. A path of width 2m runs outside around it. Find the area of path.

ANSWER

GIVEN :-

• Diameter of a circular park is 70m.

• A path of width 2m runs outside around it.

TO FIND :-

• The area of path.

FORMULA USED :-

$\bigstar \: \: \: \large\underline\blue{\bold{ \sf \:Area_{(circle)} \: = \: \pi \: {r}^{2} }}$

CALCULATION :-

• Diameter of circular park = 70 m

So,

• Radius of circular park, r = 35 m

Now,

• Path of width 2 m, runs outside around it.

So,

• Outer radius of circle, R = radius of park + width

$\rm :\implies\:R \: = \: 35 \: + \: 2$

$\rm :\implies\:R \: = \: 37 \: m$

Therefore,

$\rm :\implies\:Area_{(path)} \: = \pi \: ( {R}^{2} - {r}^{2} )$

$\rm :\implies\:Area_{(path)} \: = \pi \: ( {37}^{2} - {35}^{2} )$

$\rm :\implies\:Area_{(path)} = \dfrac{22}{7} \times (37 + 35)(37 - 35)$

$\rm :\implies\:Area_{(path)} = \dfrac{22}{7} \times 72 \times 2$

$\rm :\implies\:Area_{(path)} = 452.57 \: {m}^{2}$