q9 find x
please answer
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in given figure
angle D + angle B = 180°
(sum of either pair of opposite angles of cyclic quadrilateral is always 180°)
140°+B=180°
B=180-140
B=40°
now since AOB is diameter , angle ACB is subtended in a semi circle n thus it will be 90°
now in triangle ACB, by angle sum property
Angle A + Angle B + Angle C = 180°
x+40°+90°=180°
x=180-40-90
x=50°
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