Math, asked by rishabh0001mishra, 3 months ago

Q9) If tan²45- cos²30= x sin 30 cos 60 find the value of x.​

Answers

Answered by ishuaggarwal10
2

Answer:

  1. (1)^2 -(root3/2)^2 =x. 1/2×1/2
  2. 1 - 3/4 = x1/4
  3. 1/4×4 = x
  4. Hence x = 1
Answered by tummakeerthana19
1

Answer:

tan²45°-cos²30°=(1)²-(√3/2)²=1-3/4=4-3/4=1/4

1/4=x sin30°×cos60°

1/4=x ×1/2 ×1/2

1/4=x ×1/4

x=1

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