Q9. In Fig. 9.5, AT is a tangent to the circle with centre O such that OT = 4 cm and ∠OTA = 30°. Then AT is equal to (A) 4 cm (B) 2 cm (C) 2 √3 cm (D) 4 3 cm
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Step-by-step explanation:
ANSWER
if we join OA the OAT is a right angled triangle [since tangent is perpendicular to the circle]
so now OT=4cm,∠OTA=30
therefore from cos rule we know AT=OTcos(30)=4×
2
3
=2
3
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