Question

Q9. The denominator of a fraction 1 point
is 6 more than numerator , if the
sum of numerator and denominator
is 30 find the fraction.
14/20
ООО
O 18/24
O 12/18​

Answer 1

Given :

• The denominator of a fraction is 6 more than numerator.
• The sum of numerator & denominator is 30.

To find :

• The fraction.

Solution :

Consider,

• Numerator = x
• Denominator = y

According to the 1st condition :-

• The denominator of the fraction is 6 more than denominator.

$\to\sf{y=x+6............(i)}$

According to the 2nd condition :-

• The sum of numerator and denominator is 30.

$\to\sf{x+y=30}$

$\to\sf{x+x+6=30\:[put\:y=x+6]}$

$\to\sf{2x+6=30}$

$\to\sf{2x=30-6}$

$\to\sf{2x=24}$

$\to\sf{x=12}$

• Numerator = 12

Now put x = 12 in eq(I) for getting the value of y.

$\to\sf{y=x+6}$

$\to\sf{y=12+6}$

$\to\sf{y=18}$

• Denominator = 18

Therefore,

${\boxed{\sf{The\: fraction=\dfrac{12}{18}}}}$

Answer 2

Answer:

12/18

Step-by-step explanation:

Let the numerator be x

then, the denominator will be x+6

as they said that the denominator is 6 more than the numerator

numerator+denominator=30

i.e, x+(x+6)=30

2x+6=30

2x=30-6=24

x=24/2=12

therefore, the numerator(x) is 12 and the denominator is (x+6=12+6) 18

and the required fraction is 12/18.

Hope you got your answer my friend