Question

Q9)The roots of the quadratic equation x2+2pq=(p+2q)x are: (a)p,2q (b)-p,-2q (c)-2p,q (d)p+qp–q​

Answer 1

Answer:

${x}^{2} + 2pq = (p + 2q)x \\ {x}^{2} + 2pq = px + 2qx \\ {x}^{2} - px - 2qx +2pq = 0\\ x(x - p) - 2q(x - p) = 0 \\ (x - 2q)(x - p) = 0 \\ x = 2p \: \: , \: \: p \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$

Answer 2

Answer:

a

x²+2pq=px+2qx

Step-by-step explanation:

x²+2pq-px-2qx

x²-2qx+2pq-px

x(x-2q) -p(x-2q)

(x-p) (x-2q)

x-p=0

x-2q=0

x=p and x=2q