Question

Q9:
When 10 g of copper and 10 g of iodine are mixed, 5 g of CuI are obtained, what is the percent yield of CuI? (Cu =63.5, I = 127)
2 Cu + I2 → 2 CuI



a) 33%
b) 67%
c) 15%
d) 82%

Answer 1

Answer:

Mole of I2 = Mole of CuI

Mole of CuI = 10/127

Mass of CuI = 10/127×190.5

= 5 g

Therefore yield is 100%

Maybe your options are wrong

Please mark as brainliest