QA & PB are perpendicular to AB if AB=16cm, 0Q-5√13 cm
and op- 3√13cm. find AO & BO
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Solution:-
Given QA ⊥ AB and PB ⊥ AB so,
∠ QAO = ∠ PBO = 90° ...... (1)
In Δ AOQ and Δ BOP
∠ QAO = ∠ PBO (from equation 1)
∠ AOQ = ∠ BOP .. (vertically opposite angles)
So,
Δ AOQ is same as Δ BOP .. (by AA rule)
Then we get:
⇒ OAAQ = OBBP
⇒ 20AQ = 1218
⇒ AQ = 20 × 1812
⇒ AQ = 5 × 183
⇒ AQ = 5 × 6 = 30 cm
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